Friday

October 31, 2014

October 31, 2014

Posted by **Anonymous** on Saturday, March 10, 2007 at 12:03am.

I already found side b which equals 2 sqrts of 6.

Now I need to find the sin A and cos A. I know that sin is opposite/hypotenuse and cos is adjacent / hypotenuse. That’s as far as I can get however, I am provided with choices;

Sin A

a)7/5

b)2sqrt6/7

c)7/2sqrt6

d)5/7

Cos A

a)7/5

b)7/2sqrt6

c)2sqrt6/7

d)5/7

Please help!!!

So why not use for sine the value of a/c, and for cosine, b/c ?

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