Posted by **Anonymous** on Saturday, March 10, 2007 at 12:03am.

On a piece of paper draw and label a right triangle using the given sides, solve for the unknown side and write the trigonometric functions for angles A and B, if a=5 and c=7.

I already found side b which equals 2 sqrts of 6.

Now I need to find the sin A and cos A. I know that sin is opposite/hypotenuse and cos is adjacent / hypotenuse. That’s as far as I can get however, I am provided with choices;

Sin A

a)7/5

b)2sqrt6/7

c)7/2sqrt6

d)5/7

Cos A

a)7/5

b)7/2sqrt6

c)2sqrt6/7

d)5/7

Please help!!!

So why not use for sine the value of a/c, and for cosine, b/c ?

## Answer this Question

## Related Questions

- Math sin/cos - On a piece of paper draw and label a right triangle using the ...
- Inverse trigonometric function - How to solve without calculator 1. sin(arctan(...
- Math - Yesterday I learned to solve a right triangle assuming I know the 3 ...
- math - trig - Suppose ABC is a right triangle with sides of lengths a, b, and c ...
- Trigonometry - There is an arbitrary triangle with angles A, B, and C and sides ...
- Trigonometry - I need help with I just can't seem to get anywhere. this is as ...
- Evaluation-repost - Reposting because it has gone down to the second page! ...
- Geometry - x ________________<20* |<90* y | |<70* (hypotenuse length ...
- Trigonometry - using csc = 3.75, solve for sides: a= 3 b= ? c= ? and the ...
- math - Can anyone help w/ these. 1) Solve the equation in the internal [0deg, ...