Posted by Technoboi11 on .
A thin rod, of length L and negligible mass, that can pivot about one end to rotate in a vertical circle. A heavy ball of mass m is attached to the other end. The rod is pulled aside through an angle and released.
What is the speed of the ball at the lowest point if L = 2.20 m, = 19.0°, and m = 500 kg?
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How do I find the speed? The equations referenced are W=mgd(cos theta) and so I can solve for W but how do I get the velocity from that? PLEASE HELP!
The mass of the ball will cancel out and not matter. Use conservation of energy.
M g L (1  cos theta) = (1/2) M V^2
Theta is the angle that the ball and rod are pulled away from the vertical. Is that supposed to be 19 degrees? You have some symbols missing. L(1  cos theta) is the distance that the ball is raised in the vertical directiuon.

Physics 
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