Sunday

December 21, 2014

December 21, 2014

Posted by **dee** on Friday, March 9, 2007 at 11:14am.

x^3 + 1/2x^2 - 2x + 5

Ok I have

3x^2 + x - 2 = 0

Am I on the right track?

I think i know why I kept on asking for help with these pribelms. I forgot the step of factoring.

Please check...

3x^2 + x - 2 = 0

(3x-2)(x+1)=0

x=2/3, x=-1

Correct. Nice job.

If you calculate the second derivative (6x + 1) at those points, you can separate maxima from minima. The second derivative is negative at x = -1, making it a relative maximum.

**Answer this Question**

**Related Questions**

Calculus - Find the relative extrema and absolute extrema if any. Use the first ...

calculus - If g is a differentiable function such that g(x) is less than 0 for ...

calculus - find the relative extrema and points of inflection, if possible, of y...

Calculus - Find the relative extrema, if any, of the function. Use the second ...

calculus - f(x)=e^x-x (a) at what x-values does f have relative extrema? (b) ...

calculus - Find any relative extrema and any points of inflection if they exist ...

differentiability - If g is a differentiable function such that g(x) is less ...

Calculus - Find the relative extrema of f(x)= x/ln(x)

Calc-extrema - Find all relative and maximum extrema in ht efunction k(x)=(x^2-4...

Calc-extrema - Find all relative extrema in the function h(x)=cos(2pix/3) on the...