Tuesday
October 21, 2014

Homework Help: Calculus

Posted by dee on Friday, March 9, 2007 at 10:51am.

relative extrema

x^4-2x^2+5

so far I know how to find the derivative which is

4x^3-2x now I am stuck...
Please help

Huh?

4x^3-2x=0
2x(2x^2-1)=0
and what are the roots? I will give you a hint: one is x=0 The other two are in the second parenthesis.



Is it x-1 and x=-1

I did a typo

Is it

x-1, x+1

If you are in calc, you might want to consider some alternatives. This is pretty low level algebra. You are going to suffer with this lack of algebra understanding.

The roots of
2x(2x^2-1)=0
come from 2x=0 and 2x^2-1=0
or x=0 or x= +- sqrt (1/2)
Three roots.

Good luck.

The way that I did the problem was different than the way you did it. I had 4x(x^2-1) = 0

That is how I came up with the roots of x=0, x=1, x=-1

Was this way correct also?

No. You cannot factor 4x^3-2x the way you did. The only common factor is 2x.

4x^3-2x = 2x(2x^2-1)

The original problem was this

x^4-2x^2+5

Derivative = 4x^3-4x=0 when you factor you get 4x(x^2-1) = 0
Then you are left with x=0, x=1, x=-1.

I think you are given me the wrong answer.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Calculus - Find the relative extrema and absolute extrema if any. Use the first ...
Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...
Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...
Calculus - Given the function: f(x) = x^2 + 1 / x^2 - 9 a)find y and x ...
Calculus - Find the relative extrema, if any, of the function. Use the second ...
calculus - relative extrema x^3 + 1/2x^2 - 2x + 5 Ok I have 3x^2 + x - 2 = 0 Am ...
calculus - Find the relative extrema of f(x) = -2x^2 + 4x + 3 I don't know how ...
Calculus - 1. Find all relative extrema of the function f(x)=x^(6/7)-3. Use the ...
Math - Find the relative extrema, if any, of the function. Use the second ...
math - Find the relative extrema, if any, of the function. Use the second ...

Search
Members