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March 6, 2015

March 6, 2015

Posted by **rora** on Thursday, March 8, 2007 at 10:16pm.

anita scored 18 less than miguel, cheri's score was 16 less than twice anita's, cheri outscored jake by 21.

if the total score by all four kids was 529, what was the final scores of the match?

M (Miguel) = M

A (Anita) = M - 18

C (Cheri)= 2(M - 18) - 16

J (Jake) = [2(M - 18) - 16] -21

529 = M+(M-18)+[2(M-18)-16]+[2(M-18)-16-21]

529 = 6M + 143

M = 112

A = 94

C = 172

J = 151

- pre algebra -
**andreaa**, Tuesday, September 28, 2010 at 8:48pmwhere does the 143 come from???

- pre algebra -
**kayla**, Sunday, February 16, 2014 at 11:39amI believe that the 143 is a mistake. It should be -127.

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