A plane flying with a constant speed of 24 km/min passes over a ground radar station at an altitude of 5km and climbs at an angle of 35 degrees. At what rate, in km/min, is the distance from the plane to the radar station increasing 4 minutes later?

You should draw out a diagram, in this case a trapezoid, to help think out your calculus. Let us know if and specifically where you get stuck.

I know side a=5 but how do i get side b and c with angle 35 degree? Need help on that part.

To find side b and side c, we can use trigonometry and the given information. Since we have the angle and one side of the triangle (side a = 5 km), we can use the sine and cosine functions.

Let's label the sides of the right triangle formed by the plane's climb and the ground radar station as follows:
- Side a = 5 km (altitude)
- Side b (distance from the plane to the radar station)
- Side c (horizontal distance traveled by the plane)

Using trigonometric ratios, we can relate the side lengths as follows:
- sin(angle) = opposite/hypotenuse ---> sin(35) = 5/b
- cos(angle) = adjacent/hypotenuse ---> cos(35) = c/b

Now, let's solve for side b and side c:

1. Side b:
Using the first equation, rearrange it to solve for b:
b = 5 / sin(35)
b ≈ 8.82 km

2. Side c:
Using the second equation, rearrange it to solve for c:
c = b * cos(35)
c ≈ 7.18 km

Now we have the values for side b and side c. We can proceed to the next steps of solving the problem.