I have a few more science questions.
If a car increases its velocity from zero to 60 km/h in 10 s, its acceleration is ______ km/h/s
a.6
b.10
c.60
d.600
Is it c?
a 75kg person and a 200 kg crate are each parachuted to ear from a plane. Which is correct?
a.the crate will reach terminal velocity last, but hit the ground first.
b.the person will reach terminal velcoity last, but hit the ground first.
c.the person and crate reach terminal velocity at the same time and hit the ground at the same time.
d.the person and crate reach terminal velocity at the same time, but the crate will hit the ground first.
I am thinking A
A 75 kg astronaunt in space pushes against a 200 kg anvil. When the astonaunt lets go of the anvil while pushing it.
a.both astonaunt and anvil accelerate in opposite directions at the same rate.
b.neither the astonaunt or the anvil will accelerate since net force in zero.
c.both accelerate, but anvil accelerates more
d.both accelerate, but anvil accelerates less.
Is it B?
thanks
The first is wrong, the second depends on if the parachutes are the same size, if so, you are right.
The third, you are wrong. I am not going to do your thinking for you, but will gladly critique it. However, you are showing no thinking. Why did you choose those answers?
Hi
I am so sorry I was working on some of science stuff and switched up some of the answers. I think 1 is a.6 and 3 is c.
I have no way of knowing if the parachutes are the same size..so how am I supposed to asnwer that one?
On # 3 I am not sure how to figure that one...but I would think it would be c..that both accelerate, but and anvil will acceleterate more..becuase the anvil was being pushed
No problem! Let me help you with the correct answers and explain how to solve them.
1. The car's acceleration can be calculated using the formula: acceleration = (change in velocity) / (time taken). In this case, the change in velocity is 60 km/h (from 0 to 60 km/h) and the time taken is 10 seconds.
So, acceleration = (60 km/h) / (10 s) = 6 km/h/s.
Therefore, the correct answer is a) 6.
2. For the parachuting scenario, we need to consider two main factors: mass and terminal velocity. Terminal velocity is the maximum speed an object can reach when the drag force acting on it equals the gravitational force pulling it down.
Since the gravitational force is the same for both the person and the crate (assuming they are dropped from the same height), the terminal velocity will depend on the ratio of drag force to mass. Generally, objects with larger surface areas experience more air resistance and reach terminal velocity at a slower rate.
In this case, if the person and the crate have the same surface area and shape, they should experience a similar amount of air resistance. Therefore, they will reach terminal velocity at the same time.
However, since mass plays a role in determining the force acting on an object, the heavier crate will experience a higher force due to gravity. As a result, it will accelerate faster towards the ground, hitting the ground first.
So, the correct answer is d) the person and crate reach terminal velocity at the same time, but the crate will hit the ground first.
3. According to Newton's third law of motion, for every action, there is an equal and opposite reaction. The force exerted by the astronaut on the anvil will result in an equal and opposite force exerted by the anvil on the astronaut.
When the astronaut lets go of the anvil, the only force acting on the anvil is the force of gravity, which causes it to accelerate downward. Since there are no other forces acting on the anvil, it will accelerate at a constant rate (assuming no air resistance).
The astronaut, on the other hand, will not experience any net force, since the force exerted by the anvil in the opposite direction cancels out the force exerted by the astronaut. Therefore, the astronaut will not accelerate and will remain in place.
So, the correct answer is b) neither the astronaut nor the anvil will accelerate since the net force is zero.
I hope this helps! Let me know if you have any more questions.