# algebra

posted by
**kairi** on
.

the other one came out wrong.

8x^2y^-2 (4xy^2)^-1

________ . ___________

x^-2y x^2y

its a fraction and you have to multiply

I assume you mean

[(8x^2 y^-2)/(x^-2 y)] x [(4xy^2)^-1/(x^2 y)]

which can be rewritten

= 8 x^4 y^-3 x [1/(4x^3y^3)]

= 2 x y^-6