Posted by **Marie** on Wednesday, March 7, 2007 at 9:14pm.

write the equations of the parabola, the directrix, and the axis of symmetry.

vertex: (-4,2)

focus: (-4,6)

if someone could explain how to do this problem then that would be great! thanks in advance!

Formats to help you find the equation for a parabola:

(x - h)^2 = 4p(y - k)

Vertex = (h, k)

Focus = (h, k + p)

Directrix: y = k - p

You are given the vertex (-4,2) and the focus (-4,6).

Since we know k, which is 2, we can figure out p. Format = (h, k + p) for focus. Therefore, p = 4.

I'll set this up and let you take it from there:

[x - (-4)]^2 = 4(4)(y - 2)

The axis of symmetry is: x = -4 (vertex x-value).

I hope this will help.

good post. mathguru, if you would like to join us here at jiskha as a volunteer teacher, email me at

bobpursley@gmail.com

it did. thanks so much!

Thanks Bob! Just happy to help. :)

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