Posted by jas20 on Wednesday, March 7, 2007 at 8:34pm.
(x)/(x-2) - (x+1)/(x) = (8)/(x^2-2x)
I keep getting x = 6
can someone show me how you guys are getting x = -10
The lowest commond denominator is x(x-2)
x/x *(x)/(x-2) - (x+1)/(x) *(x-2)/(x-2)=(8)/x(x-2)
multiplying both sides by the common denominator..
x^2 -(x^2-1x -2)=8
x+2=8
x=6
check
6/4 - 7/6=8/24
36/24 - 28/24=
8/24=8/24
it checks.
OK, here's how I would go about this problem:
(x)/(x-2) - (x+1)/(x) = (8)/(x^2-2x)
(x)/(x-2) - (x+1)/(x) = (8)/x(x-2) -->factoring the denominator (x^2-2x).
Common denominator is: x(x-2)
Multiply every term by the common denominator to get rid of the fractions and make the equation easier to solve.
x(x-2) [(x)/(x-2) - (x+1)/(x) = (8)/x(x-2)]
x^2 - (x+1)(x-2) = 8
x^2 - (x^2 - x - 2) = 8
x^2 - x^2 + x + 2 = 8
x + 2 = 8
x = 6
Substitute 6 for x in the original equation. It always helps to check your work!
I hope this is clear and will help.
you get the same answer as i do but others are saying here someone named annonimous that they keep getting -10.
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