# precalculus

posted by
**Roxanne**
.

(y+1)(y+3)(5y-2)=0

That is an equation. What is the question?

Are you supposed to multiply it out or say what the solution values of y are?

posted by
**Roxanne**
.

(y+1)(y+3)(5y-2)=0

That is an equation. What is the question?

Are you supposed to multiply it out or say what the solution values of y are?