Friday
April 25, 2014

Homework Help: pre-cal

Posted by raven 31791 on Wednesday, March 7, 2007 at 11:55am.

The sq root of -4 (3-sq root of -9)

a)6 +6i
b)-6+6i
c)6-6i
d)-6-6i

Again the i's are in italics. I would think that c and d could be eliminated because the answer is suppose to be in the form a + bi but they could be trting to trick you.

I'm not quite sure what your problem is, so I'm going to assume it's something like the following:

√-4(3 - √-9)

i = √-1
i^2 = -1

Note: I'm using ^2 to mean squared.

√-4 = 2i
√-9 = 3i

Now we have: 2i(3 - 3i)

Simplifying:

6i - 6i^2 =
6i - 6(-1) =
6i + 6
..or..
6 + 6i

I hope this helps and is what you were asking.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Algebra II - The answer for (7+5i)+(-4+2i) is 3+7i. But I got -38-6i. I combined...
math,help - how can i factor this out completly x^4+x^3-12 i know that4*-3=-12 ...
Roots and Pre-cal - Find the roots of the function f(x)= x^2 +2x+2 a)-1 + sq ...
Algebra 2 - does anyone know what (4 - 6i)/(4 + 6i) = ?
Algebra - Can you explain how to find the solution of 3x^2-2x+5, using the ...
Trigonometry - I'm trying to find the cosecant of 11 pi/6. The answer is -2, but...
Algebra - I had to solve 2x^2-x-1 using the quad. formula. I got it down to (1...
Math - How does the square root of -6i-8 equal 1 +3i?
Calculus I - Find the derivative ** (sq root) y = (square root) x + (2nd sq root...
Algebra - I had to solve the function g of f where f is x^2+1 and g is sq. root ...

Search
Members