Posted by raven 31791 on Wednesday, March 7, 2007 at 11:55am.
The sq root of -4 (3-sq root of -9)
Again the i's are in italics. I would think that c and d could be eliminated because the answer is suppose to be in the form a + bi but they could be trting to trick you.
I'm not quite sure what your problem is, so I'm going to assume it's something like the following:
√-4(3 - √-9)
i = √-1
i^2 = -1
Note: I'm using ^2 to mean squared.
√-4 = 2i
√-9 = 3i
Now we have: 2i(3 - 3i)
6i - 6i^2 =
6i - 6(-1) =
6i + 6
6 + 6i
I hope this helps and is what you were asking.
Answer this Question
More Related Questions
- Roots and Pre-cal - Find the roots of the function f(x)= x^2 +2x+2 a)-1 + sq ...
- Algebra - Can you explain how to find the solution of 3x^2-2x+5, using the ...
- Math - What are the solution sets of the following 3 problems,the square root of...
- Pre-Calculus - Solve. Express your answer as exact roots. (s+6)^2 = 3/4 Sq root...
- college pre-calculus - simplify: square root (4/3)-square root (3/4) A. 2-...
- algebra - 1.)correct 2.)wrong---> the first term is wrong 4(3a^2)^2 = 36a^4 3...
- Pre-Calculus - Solve 0 = 3x^2 + 5x -1 by completing the square. Express your ...
- Trigonometry - I'm trying to find the cosecant of 11 pi/6. The answer is -2, but...
- maths surds please help and explain - Simplify A.1/root a +2 b.root 18/25 c.root...
- Algebra - Rationalize each expression by building perfect nth root factors for ...