Posted by **Jia** on Tuesday, March 6, 2007 at 9:51pm.

A plane flying with a constant speed of 24 km/min passes over a ground radar station at an altitude of 4 km and climbs at an angle of 45 degrees. At what rate, in km/min, is the distance from the plane to the radar station increasing 2 minutes later?

Rate = km/min

The vertical coordinate (in km) from the radar station is

Y = 4 + 0.707*24 t

and the horizonal coordinate is

X = 0.707*24 t

where t is in minutes.

The distance between radar station and plane is

R = sqrt (X^2 + Y^2)

take the time derivative to get dR/dt and then plug in t = 2 for the answer.

can you give me some homework about that

## Answer This Question

## Related Questions

- math - A plane flying with a constant speed of 14 km/min passes over a ground ...
- Calculus - A plane flying with a constant speed of 4 km/min passes over a ground...
- Calculus - A plane flying with a constant speed of 24 km/min passes over a ...
- calculus - A plane flying with a constant speed of 23 km/min passes over a ...
- Calculus - A plane flying with a constant speed of 5 km/min passes over a ground...
- calculas - A plane flying with a constant speed of 19 km/min passes over a ...
- MATH - A plane flying with a constant speed of 24 km/min passes over a ground ...
- Calculus test tomorrow - A plane flying with a constant speed of 24 km/min ...
- Calculus - A plane flying with a constant speed of 14 km/min passes over a ...
- Calculus - RP^2=RQ^2 + QP^2 -2(RQ)*(QP)cosQ (1) QP = 24 (km/min) t (2) ...

More Related Questions