mr.jackson is preparing bags of treats to give trick or treaters on halloween he has 48 pieces of candy and 60 pieces of gum he uses al the candy and gum and he puts the ratio of candy to gum in each bag. what is the largest number of bags he could have made?

48/60 = 4/5 so the ratio is 4 to 5

so he could make 12 bags of this ratio with this amount of treats

The answer is 12 bags.

12 bags is correct answer

To find the largest number of bags Mr. Jackson could have made, we need to determine the greatest common divisor (GCD) of the number of candy and the number of gum he has. The GCD will give us the highest possible ratio of candy to gum that he can use for each bag.

In this case, the GCD of 48 and 60 is 12. So, Mr. Jackson can make a maximum of 12 bags with the given treats.

To calculate the GCD, you can use the Euclidean algorithm. Here's how it works:

1. Divide the larger number (60) by the smaller number (48).
- 60 ÷ 48 = 1 remainder 12

2. Now, divide the smaller number (48) by the remainder (12).
- 48 ÷ 12 = 4 remainder 0

3. The remainder is 0, which means we have found the GCD. The GCD of 48 and 60 is 12.

Therefore, Mr. Jackson can make a maximum of 12 bags of treats using the ratio of 4 candy pieces to 5 gum pieces in each bag.