Posted by **jason** on Monday, March 5, 2007 at 9:03pm.

write the standard form equation of the parabola with vertex (-2,-2) that goes through point (-1,0)

y= a (x-b)^2 + c

b has to be -2, that gives the shift to the left.

y=a( x+2)^2 + c

when x=-2, y=-2, that makes c -2

y=a( x+2)^2 -2

finally, put the point -1,0 in to find a.

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