posted by Technoboi11 on .
A 2.8 kg body is at rest on a frictionless horizontal air track when a horizontal force F acting in the positive direction of an x axis along the track is applied to the body. The force F is applied to the body at t = 0, and the graph records the position of the body at 0.50 s intervals. How much work is done on the body by the applied force F between t = 0 and t = 1.0 s?
Find the distance it went:
distance= 1/2 (F/m)t^2
then work is the dot product of force and distance.