what is the equation of a line that passes through point (0,-9) with a slope of 6
(y - (-9))/(x - 0) = 6
(y+9)/x = 6
y = __ x + ___
To find the equation of a line, we can use the point-slope form. The point-slope form of a line is given by the equation:
(y - y₁)/(x - x₁) = m
where (x₁, y₁) represents a point on the line, and m is the slope of the line.
In this case, the given point is (0, -9), and the slope is 6. Plugging these values into the point-slope equation, we have:
(y - (-9))/(x - 0) = 6
Simplifying the equation:
(y + 9)/x = 6
To convert this into slope-intercept form (y = mx + b), we need to isolate y on one side of the equation. Multiply both sides of the equation by x to eliminate the fraction:
(y + 9) = 6x
Next, let's distribute the 6 to the terms inside the parentheses:
y + 9 = 6x
Finally, subtract 9 from both sides to isolate y:
y = 6x - 9
So, the equation of the line that passes through the point (0, -9) with a slope of 6 is y = 6x - 9.