Tuesday

September 16, 2014

September 16, 2014

Posted by **John** on Sunday, March 4, 2007 at 11:09pm.

a) Find the moment of inertia of the wheel. Answer in kg*m^2

(b) Find the magnitude of the frictional torque. Answer in N*m

(c) Find the total number of revolutions of the wheel.

(a) If the total torque (applied + friction)is called L,

L = Lappl + Lfric = I * alpha =

alpha is the angular acceleration, which is (9.9 rad/s)/5.95 s= 1.664 rad/sec^2

Solve for the moment of inertia, I.

b). During deceleration (with the applied force off),

alpha' = (9.9 rad/s)/59.7 s = ?

Solve again the equation

Lfric = I * alpha' for the new torque, using the value of alspha' from part (a)

(c) Calculate (add) the total number of revolutions accelerating and decelerating, N1 + N2.

N1*(2 pi) = (1/2) * alpha *(t1)^2

N2*(2 pi) = (1/2) * alpha'*(t2)^2

t1 = 5.95 s

t2 = 59.7 s

**Answer this Question**

**Related Questions**

Physics - The combination of an applied force and a frictional force produces a ...

physics - The wheel of a car has a radius of 0.390 m. The engine of the car ...

Physics - The wheel of a car has a radius of 0.390 m. The engine of the car ...

Physics - A 6 kg grinding wheel of radius 0.2 m rotates at a constant rotational...

Science - A 6 kg grinding wheel of radius 0.2 m rotates at a constant rotational...

physics - In the figure below, a constant horizontal force Fapp of magnitude 17 ...

physics - A constant torque of 20 N.m is applied to a wheel pivoted on a fixed ...

physics - A grinding wheel of radius 0.370 m rotating on a frictionless axle is ...

physics - A merry-go-round in the park has a radius of 1.8 m and a rotational ...

physics - A bicycle wheel is mounted on a fixed, frictionless axle. A massless ...