I have drawn Lewis structures for hydrogen cyanide and cyanogen. I need to state the noble gas (for each element) whose electron configuration is attained in the Lewis structures. Can anyone help as I am quite confused! Many thanks
Previous posts have asked for the noble gas configuration FOR THE MOLECULE and I have reponded that I have never heard of that. I have heard of elements being isoelectronic with a noble gas but not molecules. Yours is the first post that asks for the noble gas of each element.
For HCN, H is sharing two electrons; therefore,it is like He. C is sharing 8 electrons, it has 2 in the innner shell which makes 10 so it is isoelectronic with Ne. N has 2 electrons in the inner shell, it is sharing 8 so it is isoelectronic with Ne. You can do (CN)2 the same way.
in what way does calorimetry make use of law of conservation of energy?
heat lost by one material = heat gained by another.
You should post separate questions by clicking at the top of the page on "Post a new question."
To determine the noble gas whose electron configuration is attained in the Lewis structures of hydrogen cyanide (HCN) and cyanogen ((CN)2), you need to determine the valence electron configuration for each element and then find the noble gas that has the same electron configuration.
1. Hydrogen Cyanide (HCN):
- Hydrogen (H): Hydrogen is in Group 1 of the periodic table and has one valence electron. In the Lewis structure for HCN, hydrogen shares two electrons, forming a single bond with carbon.
- Carbon (C): Carbon is in Group 14 and has four valence electrons. In the Lewis structure for HCN, carbon shares four electrons, forming a triple bond with nitrogen.
- Nitrogen (N): Nitrogen is in Group 15 and has five valence electrons. In the Lewis structure for HCN, nitrogen shares three electrons, forming a triple bond with carbon.
To determine the noble gas configuration, count the total number of shared electrons around each atom in the Lewis structure and add it to the number of electrons in the inner shell (closest to the nucleus).
- Hydrogen (H): 2 shared electrons + 0 inner shell electrons = 2 electrons, which is the configuration of helium (He).
- Carbon (C): 4 shared electrons + 2 inner shell electrons = 6 electrons, which is the configuration of neon (Ne).
- Nitrogen (N): 3 shared electrons + 2 inner shell electrons = 5 electrons, which is also the configuration of neon (Ne).
Therefore, in hydrogen cyanide (HCN), the noble gas attained in the Lewis structure is helium (He) for hydrogen and neon (Ne) for carbon and nitrogen.
2. Cyanogen ((CN)2):
To determine the noble gas configuration for cyanogen ((CN)2), you follow a similar process.
- Carbon (C): In the Lewis structure for (CN)2, carbon shares four electrons, forming a triple bond with nitrogen. The noble gas configuration for carbon is neon (Ne), as explained earlier.
- Nitrogen (N): In the Lewis structure for (CN)2, nitrogen shares three electrons, forming a triple bond with carbon. The noble gas configuration for nitrogen is also neon (Ne), as explained earlier.
Therefore, in cyanogen ((CN)2), both carbon and nitrogen have the noble gas configuration of neon (Ne).