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December 19, 2014

December 19, 2014

Posted by **Margie** on Sunday, March 4, 2007 at 4:02pm.

4x/(x+2) - 8/(x-1)

What I did:

Common denominator is: (x+2)(x-1)

4x(x-1)/(x+2)(x-1) - 8(x+2)/(x+2)(x-1)

[4x(x-1) - 8(x+2)]/(x+2)(x-1)

multiply the numerator out.

4x^2 -4x -8x-16

4x^2-12x-16 factor 4 out

4(x^2-3x-4)

factor

4(x-4)(x+1)

and that will reduce over the denominator.

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