i have had enough,and got no hair left,i need to find the structural formula for ill try my best to explain
CH2=CH-CH-OH WITH A CH3 UNDER THE SECOND CH.+CH3-CH-C WITH A CH3 UNDER THE FIRST CH ,A DOUBLE BOND FROM THE C TO O AND A SINGLE BOND TO OH UNDER THE C,i need to find the structural formula for the product,i think there is a + H2O ,and the first is an alcohol and the second is a carboxylic acid,
i know u cant draw formula on line but please try to help im very lost
An organic acid (the R-COOH compound) reacts with an organic alcohol (the R'OH) to form an ester with the elimination of H2O as the other product. Take the OH from the RCOOH, the H from the R'OH, and combine the two compounds together at that point. You will have a RCOOR' with RC=O and the OR' coming off the C also.
I hope this helps.
To understand and draw the structural formula for the product, let's break it down step by step.
Starting with the given compounds:
- CH2=CH-CH-OH (which is an alcohol)
- CH3-CH-C (which is a carboxylic acid)
The first step is to recognize that an organic acid (RCOOH) and an organic alcohol (ROH) can react to form an ester (RCOOR') with the elimination of water (H2O). In this case, the OH group from the carboxylic acid and an H atom from the alcohol will combine to form water.
Now, let's combine the two compounds:
- Take the CH3 from CH3-CH-C and combine it with the CH2=CH-CH- from the alcohol.
- Remove the OH from the carboxylic acid and the H from the alcohol, as they will form water.
The resulting product would be:
CH3-CH-C-O-CH2=CH-CH3
In this structure, the C=O bond represents the carbonyl carbon of the ester, and the O-CH2=CH-CH3 group represents the combined alcohol and carboxylic acid units.
Please note that without knowing the specific names or substituents for the compounds involved, the naming and placement of functional groups cannot be provided accurately. However, the structure above should represent the product formed by the reaction between the given compounds.