Can someone please help me balance this equation?

CH3OH + O2 ===> CO2 + H20

Thank you!



CH3OH + O2 ===> CO2 + H2O
To balance the H, put a two on the right.
CH3OH + O2 ===> CO2 + 2H20
H and C are now balanced. O is balanced.
Too easy.

Are you sure that's right? We got an answer key with the problems and it says the answer is: 2CH3OH + 302 ==> 2CO2 + 4H20

I just don't know how to get to that.

Actually, I think yours is right.

The key is right.
Two C on left and right.
8H on left and 8 on right.
8 O on left and 8 on right.

So are they both right?

Oh, sorry my name changed. I'm on my sister's computer.

Do they both add up> Count the atoms on each side. Then you will know the answer to your question.

okay thanks

You're welcome! To balance the equation CH3OH + O2 => CO2 + H20, you can follow these steps:

1. Start by counting the number of atoms on each side of the equation.

On the left side:
C: 1
H: 4
O: 1

On the right side:
C: 1
H: 2
O: 3

2. Begin by balancing the carbon (C) atoms. As you can see, there is already one carbon atom on both sides, so the carbon is already balanced.

3. Next, balance the hydrogen (H) atoms. On the left side, there are four hydrogen atoms, while on the right side, there are only two. To balance them, you can put a coefficient of 2 in front of H2O:

CH3OH + O2 => CO2 + 2H2O

Now, counting the atoms again:

On the left side:
C: 1
H: 4
O: 1

On the right side:
C: 1
H: 4
O: 4

4. Lastly, balance the oxygen (O) atoms. There are three oxygen atoms on the left side, but four on the right. To fix this, you need to add a coefficient of 3 in front of O2:

2CH3OH + 3O2 => 2CO2 + 4H2O

Now, counting the atoms one more time:

On the left side:
C: 2
H: 8
O: 6

On the right side:
C: 2
H: 8
O: 6

With these coefficients, the equation is balanced.