# Algebra

posted by
**Palace**
.

How do I solve this?

The perimeter of a rectangular writing pad is 28 inches. The length is 1 inch

less than twice the width. Find the width.

Show all work!

Translate your English into Math

<The length is 1 inch

less than twice the width>

or L = 2W - 1

<Perimeter is 28 inches>

2L + 2W = 28

2(2W-1) + 2L = 28

I am sure you can solve this

I am just beginning to learn this stuff.

The answer is 7 right?

no

starting from 2(2W-1) + 2L = 28

4w - 2 + 2L = 28

6W = 28+2

6W=30

W = 5 the L = 2W-1

= 10-1

= 9

check 2(9) + 2(5) = 28

Are you sure? I have 4 choices on my

assignment to mark and 9 isn't on there.

The choices are:

A. 8 inches

B. 7 inches

C. 6 inches

D. 5 inches

Yes I am sure.

My answers were W=5 L=9

notice i had verified my answer.

The original equation should be:

2(2w-1)+ 2w = 28 (It used L in the first equation, but L was replaced by 2w-1)

Distribute first:

4w-2 + 2w = 28

Combine like terms:

6w - 2 = 28

Solve:

6w = 30

w = 5

The correct answer is D. Double check it in the original equation.