Posted by **Jason L** on Friday, March 2, 2007 at 8:23am.

A specially equipped trauma emergency room at a hospital has been in operation for 40 weeks and has been used a total of 108 times. Assuming the weekly pattern of demand for this facility is poisson compute the following -

probability room is not used in a given week

probability that the room is used 7 or more times in a week

the mean demand for a 2 week period

Assume the true probablity of uses per week is L = 108/40 = 2.7, as established by the rather large sample.

The probability that there will be k occurences is

P(k) = e^-L*L^k/k!

Where p is the Poisson distribution function.

(See

http://en.wikipedia.org/wiki/Poisson_distribution )

For k = 0, P = e^-2.7 = 0.067

That is the probability there will be zero uses in one week.

Fot k = 7, P = e^-2.7*2.7^7/7! = 0.0139

for k = 8, P = 0.0047

For k = 9, P = 0.0014

P for k>9 is negligible. The total probability for k equal to or greater than 7 will be 0.020

The average number of uses in 2 weeks is just 2.7/week x 2 weeks = 5.4

## Answer This Question

## Related Questions

- Statistics - A specially equipped trauma emergency room at a hospital has been ...
- statistics - If 20% of the people in a community use the emergency room at a ...
- Marketing - The emergency room staff in Houston's largest hospital is surprised ...
- English - 1. He spent two weeks in hospital. 2. He spent two weeks in the ...
- Grammar-Capitalization - What should be capitalized. the child was picked up by ...
- Alliedhealth - A woman is brought into an emergency room after a severe ...
- health - A woman is brought into an emergency room after a severe automobile ...
- health - Write a 700- to 1,050-paper responding to the following: You have ...
- ethics - The rising number of uninsured patients has led to an increased ...
- ethics - The rising number of uninsured patients has led to an increased ...

More Related Questions