Saturday

December 20, 2014

December 20, 2014

Posted by **Jason L** on Friday, March 2, 2007 at 8:23am.

probability room is not used in a given week

probability that the room is used 7 or more times in a week

the mean demand for a 2 week period

Assume the true probablity of uses per week is L = 108/40 = 2.7, as established by the rather large sample.

The probability that there will be k occurences is

P(k) = e^-L*L^k/k!

Where p is the Poisson distribution function.

(See http://en.wikipedia.org/wiki/Poisson_distribution )

For k = 0, P = e^-2.7 = 0.067

That is the probability there will be zero uses in one week.

Fot k = 7, P = e^-2.7*2.7^7/7! = 0.0139

for k = 8, P = 0.0047

For k = 9, P = 0.0014

P for k>9 is negligible. The total probability for k equal to or greater than 7 will be 0.020

The average number of uses in 2 weeks is just 2.7/week x 2 weeks = 5.4

**Answer this Question**

**Related Questions**

Statistics - A specially equipped trauma emergency room at a hospital has been ...

statistics - If 20% of the people in a community use the emergency room at a ...

Grammar-Capitalization - What should be capitalized. the child was picked up by ...

Marketing - The emergency room staff in Houston's largest hospital is surprised ...

Alliedhealth - A woman is brought into an emergency room after a severe ...

health - A woman is brought into an emergency room after a severe automobile ...

ethics - The rising number of uninsured patients has led to an increased ...

ethics - The rising number of uninsured patients has led to an increased ...

broadcasting/english - feedback is appreciated, thanks in advance THOUSANDS OF ...

Calculus for Business students - A hospital performs 3 types of operations. The ...