Posted by CJ on Friday, March 2, 2007 at 2:53am.
A 2.50g bullet, traveling at a speed of 425m/s, strikes the wooden block of a ballistic pendulum. The block has a mass of 270g
(a) find the speed of the bullet/block combination immediately after the collision
(b) how high does the combination rise above its initial position?
(a) (bullet mass) x (bullet initial velocity) = (total mass) x (speed of bullet & block)
Solve for (speed of bullet & block)
(b) since kinetic energy of bullet & block = increase in potential energy at top of swing
g h = (1/2) (speed of bullet & block)^2

Physics  sicheng the tool, Monday, April 22, 2013 at 9:16pm
sicheng is a tool

Physics  rh, Tuesday, March 22, 2016 at 6:20am
kh

Physics  Lolu, Thursday, July 14, 2016 at 11:04am
1209
Answer This Question
Related Questions
 Physics  A 2.50 g bullet, traveling at a speed of 435 m/s, strikes the wooden ...
 physics  A 3.67g bullet, traveling at a speed of 484 m/s, strikes the wooden ...
 Physics  A 2.86g bullet, traveling at a speed of 452 m/s, strikes the wooden ...
 Physics  A 3.30g bullet, traveling at a speed of 492 m/s, strikes the wooden ...
 Physic  A bullet strikes a ballistic pendulum whose target block has a mass of ...
 Physics  A 10 kilogram block initially hangs at rest at the end of two 10 meter...
 Physics  A bullet with a mass m=12.5 g and speed v=85.4 m/s is fired into a ...
 physics  A bullet with mass m = 5.21 g is moving horizontally with a speed v=...
 physics  A 2.50 g bullet, traveling at a speed of 485 m/s, strikes the wooden ...
 physics  at on time, the velocity of a rifle bullet was measured using a ...
More Related Questions