Posted by Technoboi11 on Friday, March 2, 2007 at 12:19am.
A single force acts on a 5.0 kg particlelike object in such a way that the position of the object as a function of time is given by x = 3.0t  4.0t 2 + 1.0t 3, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 2.0 s.
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* Physics/Math  bobpursley, Thursday, March 1, 2007 at 6:28am
find the position at at t=2 and t=0. The difference in those is the displacement.
Work= force times displacement.
* Physics/Math  Technoboi11, Friday, March 2, 2007 at 12:11am
So when t=0, x=0.
When t=2, x=2
displacement= 20 = 2m
W=Fd
F=ma=(5)(9.8)=49
W=(49 N)(2 m)
W= 98 J
This is the answer that I got but it is an incorrect answer. Is there something wrong with my calculations???

University at Buffalo  Ryan, Sunday, October 16, 2011 at 3:26pm
Working on this myself. Use the work energy theorem.