Posted by **Technoboi11** on Friday, March 2, 2007 at 12:19am.

A single force acts on a 5.0 kg particle-like object in such a way that the position of the object as a function of time is given by x = 3.0t - 4.0t 2 + 1.0t 3, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 2.0 s.

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* Physics/Math - bobpursley, Thursday, March 1, 2007 at 6:28am

find the position at at t=2 and t=0. The difference in those is the displacement.

Work= force times displacement.

* Physics/Math - Technoboi11, Friday, March 2, 2007 at 12:11am

So when t=0, x=0.

When t=2, x=-2

displacement= -2-0 = -2m

W=Fd

F=ma=(5)(9.8)=49

W=(49 N)(-2 m)

W= -98 J

This is the answer that I got but it is an incorrect answer. Is there something wrong with my calculations???

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