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calculus

posted by on .

derivatives

differentiate

y=x^7/3

So far I have

Y=7/3X

Is this all there is to this problem?

Using the power rule, you bring the exponent down, just like you did. Then, you subtract one from the given exponent to get the new exponent. 7/3 - 1 (which is 3/3) gives you a new exponent of 4/3. Your answer should be:

7/3 x^4/3

Hope that helped!
Amy :)

Thanks...

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