Posted by **Elizabeth** on Thursday, March 1, 2007 at 3:17pm.

i need help finding the slope of the line that passes through each pair of poinst.

1. (1,-3),(4,3)

2.(5,0), (-2,1)

Divide (y2 - y1) by (x2 - x1). For (1), this would be 6/3 = ?

Thank you. The first one came out to 2.

The second one is not working out. I got 4 1/2 and I know that's not correct. I did (-2x2)-(5x1) divide by

(1x2)-(0x1)= -9/2

Don't multiply. (x2-x1) just means taking the second x value and subtracting the first x value from it. So as far as the x values go for the second problem, you'll have (-2 -5). As far as the y's go, you take the second y and subtract the first y. (1-0).

Can you get it from there?

Amy :)

I think I got it.

I redid both.

(1,-3) (4,3); 3-(-3)=6 divided by 4-1=3

(5,0) (-2,1); 1-0=1 and -2-5=-7 so -1/7 is the slope. I hope that's correct?

(1-0)/(-2-5) = -1/7, so that's correct.

YEA!

YEA!

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