I don't want to get this wrong for this homework that i have to turn in can someone please relook at it and tell me if it is correct plz....

solve. x^2+3x-18

my answer is x=3 and x=-6

yes.

To verify if your solution is correct, we need to solve the equation x^2 + 3x - 18.

To solve a quadratic equation of the form ax^2 + bx + c = 0, where a, b, and c are constants, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = 1, b = 3, and c = -18. Plugging these values into the quadratic formula, we get:

x = (-3 ± √(3^2 - 4(1)(-18))) / (2(1))

Simplifying further:

x = (-3 ± √(9 + 72)) / 2
x = (-3 ± √81) / 2
x = (-3 ± 9) / 2

Now we have two possible solutions:

1. x = (-3 + 9) / 2 = 6 / 2 = 3
2. x = (-3 - 9) / 2 = -12 / 2 = -6

Therefore, your answer of x = 3 and x = -6 is correct. Well done!