Posted by **Jean** on Thursday, March 1, 2007 at 6:09am.

Calculate the force required to pull a copper ball of radius 2.00 cm upward through a fluid at the constant speed 9.00 cm/s. Take the drag force to be proportional to the speed, with proportionality constant 0.950 kg/s. Ignore the buoyant force.

Forcedrag=k v

= .950kg/s * .09m/s= ? joules

I got this answer too.

but the book says the answer is 3.01 N up?

Total force required = Weight + drag = (4/3) pi R^3 * density * g

+ (0.950) kg/s * 9*10^-2 m/s

Use g = 9.8 m/s^2,

R = 2*10^-2 m,

and density = 8.92*10^3 kg/m^3

AHHH!

thank you SO much.

can i ask you how you got the

"weight" part of the equation?

Weight = Mass * g = Volume*density* g

The answer will be in Newtons, by the way

- Physics -
**Anonymous**, Monday, April 4, 2016 at 1:26am
fdv

## Answer This Question

## Related Questions

- Physics - Calculate the force required to pull a copper ball of radius 2.00 cm ...
- Physics - Calculate the force required to pull a copper ball of radius 2.00 cm ...
- Physics please help - Calculate the force required to pull a copper ball of ...
- Physics - A sky diver of mass 80.0 ks jumps from a slow-moving aircraft and ...
- physics - A leather ball of circumference 75.9 m and mass 557 g is forced to the...
- Physics - A 59-kg housepainter stands on a 16-kg aluminum platform. The platform...
- physics - A ball of circumference 74.2 cm and mass 605 g is forced to the bottom...
- Physics - A mixing beater consists of three thin rods, each 10.9 cm long. The ...
- physics - A Chinook salmon has a maximum underwater speed of 3.0 m/s, and can ...
- Physics - this one is kind of hard A bicyclist can coast down a 7.0 degree hill ...

More Related Questions