Posted by **Jean** on Thursday, March 1, 2007 at 6:09am.

Calculate the force required to pull a copper ball of radius 2.00 cm upward through a fluid at the constant speed 9.00 cm/s. Take the drag force to be proportional to the speed, with proportionality constant 0.950 kg/s. Ignore the buoyant force.

Forcedrag=k v

= .950kg/s * .09m/s= ? joules

I got this answer too.

but the book says the answer is 3.01 N up?

Total force required = Weight + drag = (4/3) pi R^3 * density * g

+ (0.950) kg/s * 9*10^-2 m/s

Use g = 9.8 m/s^2,

R = 2*10^-2 m,

and density = 8.92*10^3 kg/m^3

AHHH!

thank you SO much.

can i ask you how you got the

"weight" part of the equation?

Weight = Mass * g = Volume*density* g

The answer will be in Newtons, by the way

- Physics -
**Anonymous**, Monday, April 4, 2016 at 1:26am
fdv

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