Wednesday
May 4, 2016

Posted by Angie on Thursday, March 1, 2007 at 12:32am.

It's been so long I forget which ones are which. My balanced equation is Sr(NO3)2 + 2KIO3 --> Sr(IO3)2 + 2KNO3.

It wants the total ionic
and the net ionic

Thanks ^^ (not just looking for answer, want explanation too please, just a short one)

In aqueous solution, this would look this way.
Sr(NO3)2(aq) + 2KNO3(aq) ==> Sr(IO3)2(s) + 2KNO3(aq) where (aq) stands for aqueous solution and (s) stands for solid (meaning it is insoluble in water).
Total ionic equation:
Write each soluble compound as ions but leave the insoluble one as solid. Like so. Each ion will have (aq) but that is time consuming. You can add it in. I put it on the first ion; you do the others.
Sr^+2(aq) + 2NO3^- + 2K^+ + 2IO3^- ==>Sr(IO3)2(s) + 2K^+ + 2NO3^-

With the (aq) added to the others (but not the solid), this is the total ionic equation. To obtain the net ionic equation, simply cancel those ions that appear on both sides of the equation. What is left will be the net ionic equation. The net ionic equation is
Sr^+2(aq) + 2IO3^-(aq) ==> Sr(IO3)2(s)

Thank you, I had done them, but had a bit wrong in them ^^