Can someone correct these for me plz...

Problem#6
Factor. x(x-5)-2(x-5)

My answer is: (x-2)(x-5)

Problem#7

Factor completely. x^2-x-6

My answer is: (x+2)(x-3)

Problem#8
Factor completely. 35x^2+40x+5

My answer is: (7x+1)(5x+5)

Problem #9
Factor by grouping. x^3-5x^2+2x-10

MY answer is: (x-5)(x^2+2)

Problem#10

Solve. x^2+3x-18=0

My answer is the value of x are

x = 3 and x = -6

They are all correct answers

thank you.....that releaves my stress...

Problem #6:

To factor the expression x(x-5)-2(x-5), you can first recognize that (x-5) is a common factor in both terms. You can then factor out this common factor to obtain:

x(x-5) - 2(x-5) = (x-5)(x-2)

Therefore, your answer of (x-5)(x-2) is correct.

Problem #7:

To factor the polynomial x^2-x-6, you can look for two numbers that, when multiplied, give you -6, and when added, give you -1 (the coefficient of the linear term). The numbers that satisfy these conditions are -3 and 2.

Therefore, you can factor the polynomial as:

x^2 - x - 6 = (x + 2)(x - 3)

So, your answer of (x+2)(x-3) is correct.

Problem #8:

To factor the polynomial 35x^2 + 40x + 5, you can look for two numbers that, when multiplied, give you 35 (the coefficient of the quadratic term times the constant term), and when added, give you 40 (the coefficient of the linear term). The numbers that satisfy these conditions are 5 and 7.

Therefore, you can factor the polynomial as:

35x^2 + 40x + 5 = (5x + 1)(7x + 5)

So, your answer of (7x+1)(5x+5) is correct.

Problem #9:

To factor the expression x^3 - 5x^2 + 2x - 10, you can try to group terms together. Group the first two terms and the last two terms:

(x^3 - 5x^2) + (2x - 10)

Notice that you can factor out an x^2 from the first grouping and a 2 from the second grouping:

x^2(x - 5) + 2(x - 5)

Now, you can factor out the common factor (x - 5):

(x - 5)(x^2 + 2)

So, your answer of (x-5)(x^2+2) is correct.

Problem #10:

To solve the equation x^2 + 3x - 18 = 0, you can try factoring or applying the quadratic formula.

In this case, factoring gives you:

(x + 6)(x - 3) = 0

Setting each factor equal to zero, you get:

x + 6 = 0 --> x = -6
x - 3 = 0 --> x = 3

So, your answer of x = 3 and x = -6 is correct.