Posted by **Reisha** on Wednesday, February 28, 2007 at 5:17pm.

Find the relative extrema of the functions.

f(x)=4x/(x^2+1)

f(x)=1/(x-2)

take the derivative, set to zero.

the first as an example:

f(x)= 4x (x^2 +1)^-1

f'(x)= 4 (x^2 +1)^-1 -4x(2x)(x^2 +1)^-2

set to zero. Multiply thru by (x^2+1)^2

0=4(x^2+1) - 8x^2

4x^2=1

x= +- 1/2

what about the second question

f(x)1/(x-2)

## Answer this Question

## Related Questions

- Calculus - find the intervals on which f(x) is increasing and decreasing along ...
- Calculus--> bobpursley - How do you get m=0? from taking the second ...
- CALCULUS!!! - case 1. Find the absolute maxima and minina values of f(x)=sin2x+...
- Math - I dont understand this!!! If rstv=1 and stuv=0, which of the followin ...
- Calculus - What is the point of inflection of the function f(x)=x^3-8x^2+5x+50? ...
- Calculus - Explain the global optimization process for a continuous function ...
- Calculus - Find the relative extrema and absolute extrema if any. Use the first ...
- math - Let S be the set of all measurable functions on [0,1]. Then the set O of ...
- Calculus - R=M^2(c/2-m/3) dR/dM=CM-M^2 I found the derivative. Now how would I ...
- Calculus Please check - Please check my answers and let me know if I did ...