Look on your calculator. You know the definition of pH. It is pH=-log(H^+). Well, we have the same thing in pKa, pKb, pOH, pKw, etc etc.

pKsp = -log Ksp.
Punch 57.685 into the calculator. Now change the sign to make it negative. Now look for a button that says 10x and punch that. The answer is something like ??? x 10^-58.
Try it. You'll like it.

A really weird salt of the type A3B4 is put into water and the saturated solution forms. For this salt, pKsp = 57.685. What is the base-10 log of the solubility? (Need logarithm for answer)

Can someone give me some steps to follow?

is it 2.065e-58 ?

If so, how do I give that answer as a logarithm? This might sound kind of silly, but I haven't done logs in awhile... but does that mean the answer needs to contain "log" of something?

Thanks

Yes, that's the answer.
If pKsp= 57.685, then
Ksp= 2.065 x 10-58.
The "logarithm" is in the formula for the conversion.

To find the base-10 log of the solubility, you can use the logarithm function on your calculator. Here are the steps:

1. Start with the value of Ksp, which is 2.065 x 10^-58.
2. Press the negative button (-) on your calculator to change the sign to negative.
3. Look for a button on your calculator that says "10^x" or "10^" and press it.
4. Enter the negative value, in this case, -58.
5. Press the equals (=) button on your calculator to get the result.

The answer you should get is something like 2.065 x 10^-58.

Now, to express this answer as a logarithm, you need to understand that the base-10 logarithm (log) of a number is the exponent to which 10 must be raised to obtain that number. In this case, the solubility is 2.065 x 10^-58, so the logarithm of this value would be -58.

Therefore, you can express the base-10 log of the solubility as -58.