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October 24, 2014

October 24, 2014

Posted by **jas20** on Tuesday, February 27, 2007 at 6:41pm.

factor by grouping

x^3-3x^2+4x-12

so what i have so far is this

=(x^3-3x^2)+(4x-12)

=x(x^2-3x)+4(x-3)

from here i don't know...

and then this one is driving me insane this next one...

Rewrite the middle term as the sum of two terms and then factor by grouping.

x^2-14x+45

i'd figure out problem #1

these are the steps I did:

factor by grouping

x^3-3x^2+4x-12

so what i have so far is this

=(x^3-3x^2)+(4x-12)

=x^2(x-3)+4(x-3)

= (x-3)(x^2+4)

I AM STILL HAVING TROUBLE WITH PROBLEM NUMBER 2

to your second question

wouldnt it be-

(x-5)(x-9)

You have to find 2 numbers to multiply to bed 45 BUT add to be negative 14.

yes,thank you......

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