Thursday

November 27, 2014

November 27, 2014

Posted by **Cavin** on Tuesday, February 27, 2007 at 9:03am.

At the bottom of his swing, he has lost gravitational potential energy

PE = 2 M g * 1.1 m

If all his mass were at his waist, the velocity of the waist would be given by

KE = (1/2)M V^2 = 2 M g * 1.1 m,

because the potential energy loss would be cnverted to kinetic energy.

Cancel out the unknown M and solve for V.

V = sqrt (4*g*1.1 m)

**Answer this Question**

**Related Questions**

AP PHYSICS - A gymnist is swinging on a high bar. The distance between his waist...

physics - A gymnast is swinging on a high bar. The distance between his waist ...

physics - a uniform bar of mass is supported by support pivoted at top about ...

physics - if theta is the angle between unit vectors A bar and B bar, then (1-A ...

PHYSICS - There's a bar with length of 6.49m and mass of 5.45kg leaning against ...

physics - bar subjected to gravity load (two segments) the bar in the fig has ...

physics - bar subjected to gravity load (two segments) the bar in the fig has ...

physics - bar subjected to gravity load (two segments) the bar in the fig has ...

Physics Classical Mechanics - A bar of mass m and negligible height is lying ...

classical mechanics - A bar of mass and negligible height is lying horizontally...