Tuesday

March 31, 2015

March 31, 2015

Posted by **Jill** on Monday, February 26, 2007 at 9:30pm.

y^2 + y/x - 1/x^2 = 0

Treat 1/x as b and -1/x^2 as c in the quadratic equation ax^2 + bx + c = 0

There are two solutions

y = [-1/x + sqrt(1/x^2 + 4/x^2)]/2

and

y = [-1/x - sqrt(1/x^2 + 4/x^2)]/2

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