Monday
April 21, 2014

Homework Help: More Math 2 See If You Can Help Me... :)

Posted by Margie on Monday, February 26, 2007 at 6:22pm.

Problem:
a^2-9 a^2-3a
----- * --------
a^2 a^2+a-12
Here Is What I Got:
(a+3)3a
-------
(a+4)
*Please Check It.I think I did it wrong though.. =[

I'm going to assume your problem is this:

(a^2-9)/a^2 * (a^2-3a)/(a^2+a-12)

Note: I'm using * to mean multiply.

If that is the problem, then you want to try to factor first, so you can reduce wherever you can.

Factoring:
(a+3)(a-3)/a^2 * a(a-3)/(a+4)(a-3)

Cancel out (a-3) in both the numerator and denominator of the second fraction to end up with this:

(a+3)(a-3)/a^2 * a/(a+4)

Multiplying:
a(a+3)(a-3)/a^2(a+4)

We can still reduce a/a^2 to end up with this:
(a+3)(a-3)/a(a+4)

And that's about as far as we can go on this one!

I hope this helps and is what you were asking for this problem.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

algebra - Given f(x) = 2x - 5, find f(-3a). F(x)= 2(-3a) -5 F(-3a) = 2(3a)-5 = 1...
math - simplify 12b^-6/3a^0 you should read my notes on "rob"'s questions if you...
Math(Please Check My Work.) - 3a^3b^2(-a^3b-a^2b^2)=-3a^9b^3-3a^6b^4 *is this ...
Pre-Calc-please check - Please check this for me expand (3z-2b)^5 using Binomial...
Math - Factor each expression 1-9a^2/a+1 times 4x^2-y^2/x+y Here is what I got...
math binomial expansion - binomial expansion (3a^2-2b^3)^4 is this right? (3a^2...
Math2[Please Check Again] - Problem: a^2-9 a^2-3a ----- * -------- a^2 a^2+a-12 ...
Math - Factorize the following expressions: 1) 6a(3a-2)+12b(3a-2) I got : (3a-2...
Math- factoring - Show all work and factor completely. 6a^2+5a-4 (6a^2+8a)-(3a-4...
algebra - So here's the problem: 6a^-2 + 9a^2 all over 3a^-2 The answer is ...

Search
Members