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April 1, 2015

Homework Help: RE: PHYSICS

Posted by COFFEE on Monday, February 26, 2007 at 4:10pm.

"Relative" is an important word. Block L of mass mL = 1.90 kg and block R of mass mR = 0.500 kg are held in place with a compressed spring between them. When the blocks are released, the spring sends them sliding across a frictionless floor. (The spring has negligible mass and falls to the floor after the blocks leave it.)
(a) If the spring gives block L a release speed of 1.80 m/s relative to the floor, how far does block R travel in the next 0.800 s?
(b) If, instead, the spring gives block L a release speed of 1.80 m/s relative to the velocity that the spring gives block R, how far does block R travel in the next 0.800 s?

For Further Reading

* Physics - bobpursley, Sunday, February 25, 2007 at 5:22pm

Momentum L has is equal to the momentum R has.

1.90*1.80=.500*veloictyR


Relative to each other, velocityLrelative=VelocityRrelative

Now to compute the distance here, obviously the relative distances are of no value....they equal each other. Here you have to convert to an absolute relative to floor velocity. AGain, use the principle that the center of gravity is constant, or, the momentums are equal.

* Physics - COFFEE, Sunday, February 25, 2007 at 11:47pm

1.9*1.8=.5*velocityR
velocityR = 6.84 m/s

d=v*time
d=(6.84)(.8)
d=5.472m ???

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