Posted by
**Jason L** on
.

In a particular suburb 30% of housholds have installed electronic security systems. If 2 households are chosen at random from this area, what is the probability that neither has installed a security system?

Using the binomial probability function for this problem:

P(x) = (nCx)(p^x)[q^(n-x)]

p = .3

q = 1 - p = .7

x = 0

n = 2

P(0) = (2C0)(.3^0)(.7^2)

Finish the calculation for your probability.