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August 30, 2014

August 30, 2014

Posted by **Jason L** on Monday, February 26, 2007 at 3:23pm.

You can use the normal approximation to the binomial distribution.

Your values are the following:

p = 1/100 = .01, q = 1 - p = 99/100 = .99, x = 14, and n = 600

You need to find mean and standard deviation.

mean = np = (600)(.01) = 6

standard deviation = √npq = 2.44 (this is a rounded value)

Now use z-scores to find probability:

z = (x - mean)/sd -->sd = standard deviation

With your data:

z = (14 - 6)/(2.44) = 3.28

Using a z-table, you will find the probability to be very small.

I hope this will help.

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