posted by Cavin on .
A shot putter puts a shot (weight=70.3N) that leaveshis hand at distance of 1.51m above the ground.
(a) Find the work done by the gravitatiob force when the shot has risen to a height of 2.10m above the ground. include the correct sign for work.
(b) Determine the change in the gravitational potential energy of the shot.
a) Since work is done against the gravitational force, the sign is negative. The magnitude is
M g (delta h),
where "delta h" is the height change, 0.59 m, gi is the acceleration of gravity and M is the mass.
b) This would be the same nummber with opposite (positive) sign.