Wednesday

January 28, 2015

January 28, 2015

Posted by **christine** on Monday, February 26, 2007 at 12:29am.

s 1/ [ (x^4) sq.rt(x^2+9)]

i know x=3tanx

sq.rt(x^2+9)= 3 secx

dx= 3/[cos^2(x)]

so far i know:

= 1/ (3tan^4(x)) 3secx cos^2(x)) dx

=1/ 81 [ (sin^4 (x)/cos^4 (x)) (1/cosx) (cos^2(x))]

then i'm not really sure what to do next

**Answer this Question**

**Related Questions**

Calculus - Integration - Hello! I really don't think I am understanding my calc ...

Calc BC - 1. Find the indefinite integral. Indefinite integral tan^3(pix/7)sec^2...

Calculus - I have two questions, because I'm preparing for a math test on monday...

Integral - That's the same as the integral of sin^2 x dx. Use integration by ...

Pre-Calc - Trigonometric Identities Prove: (tanx + secx -1)/(tanx - secx + 1)= ...

math - find the integral secxtanxdx and if dy/dx= 2x/y^2 and y(o) = 3 then what ...

trig - it says to verify the following identity, working only on one side: cotx+...

TRIG! - Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6...

please help me calc. have test tom - d/dx integral from o to x of function cos(2...

Calc. - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x ln...