How much water needs to be added to 150mL of an 0.75 molar solution of lithium phosphate to make the solution 0.625 molar?
I came up with 70.31mL
Can you someone just check this for me please?
you want to dilute it 75/62.5, so you are diluting it a factor of 1.2, so add .2 parts water.
150*.2 = ???? ml
So my answer should be 30 not 70
To dilute a solution, you need to know the initial volume and concentration, as well as the desired final concentration.
In this case, we have:
Initial volume (Vi) = 150 mL
Initial concentration (Ci) = 0.75 M
Final concentration (Cf) = 0.625 M
To find out how much water needs to be added, we can use the formula:
Vi x Ci = Vf x Cf
Substituting the given values:
150 mL x 0.75 M = Vf x 0.625 M
Now, solving for Vf:
150 x 0.75 / 0.625 = Vf
Vf ≈ 180 mL
Therefore, you need to add about 180 mL of water to 150 mL of the 0.75 M lithium phosphate solution to obtain a final concentration of 0.625 M.
So, your initial answer of 70.31 mL is incorrect. The correct amount is approximately 180 mL.