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February 1, 2015

February 1, 2015

Posted by **Jill-** on Sunday, February 25, 2007 at 10:16pm.

did you mean (x^2)(y^2) + xy = 1 ???

If so, are you solving for x or y?

Suggestion: let xy = a, then you have the equation a^2 + a - 1 = 0

solve it as a quadratic and a = (-1 +-sqr(5))/2

so xy = (-1+-sqr(5))/2 or the other root.

solve this for either x or y.

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