The question says Sufuric acid reacts with Aluminum hydroxide by double replacement.
I have the reactant side I just need the product side because I need to know does aluminium replace Hyrdrogen, really confused
hydroxides react with acids to form a salt and water.
Products are aluminum sulfate and water.
So it is H2SO4 + Al(OH)3====>Al2(SO4)3 +HOH
To determine the products of the reaction between sulfuric acid (H2SO4) and aluminum hydroxide (Al(OH)3), we need to understand the concept of double replacement reactions.
In this type of reaction, the cations of the two compounds switch places to form new compounds. Aluminum has a +3 charge (Al3+), while hydrogen has a +1 charge (H+). The sulfate ion (SO42-) and hydroxide ion (OH-) will remain the same.
So, when sulfuric acid reacts with aluminum hydroxide, aluminum will replace hydrogen to form aluminum sulfate. Meanwhile, the hydroxide ion will combine with the hydrogen ion to form water.
Therefore, the balanced equation for this reaction is:
H2SO4 + Al(OH)3 → Al2(SO4)3 + H2O
The products are aluminum sulfate (Al2(SO4)3) and water (H2O).