The question says Sufuric acid reacts with Aluminum hydroxide by double replacement.

I have the reactant side I just need the product side because I need to know does aluminium replace Hyrdrogen, really confused

see Ms J question above

To determine the products of the reaction between sulfuric acid (H2SO4) and aluminum hydroxide (Al(OH)3), we need to understand the concept of double replacement reactions. In a double replacement reaction, the positive ions of two compounds switch places to form new compounds.

First, let's look at the reactant side:

H2SO4 + Al(OH)3

In sulfuric acid (H2SO4), we have two hydrogen ions (H+) and one sulfate ion (SO4^2-). In aluminum hydroxide (Al(OH)3), we have one aluminum ion (Al^3+) and three hydroxide ions (OH^-).

In a double replacement reaction, the positive ions will switch partners. The hydrogen ions (H+) will combine with the hydroxide ions (OH^-) to form water (H2O), while the aluminum ion (Al^3+) will combine with the sulfate ion (SO4^2-) to form aluminum sulfate (Al2(SO4)3).

So, the balanced chemical equation for the reaction is:

3H2SO4 + 2Al(OH)3 -> Al2(SO4)3 + 6H2O

In conclusion, the products of the reaction between sulfuric acid and aluminum hydroxide are aluminum sulfate and water. Aluminum replaces hydrogen in this reaction.