Posted by **Christy** on Saturday, February 24, 2007 at 9:44pm.

A 75 kg box slides down a 25 degree ramp with an acc. of 3.6 m/s2. find mu,k between the box and the ramp.

Write down Newton's second law for the direction of motion. "a" is the acceleration.

Mg sin 25 - M g cos 25 *mu,k = M a

The first term is the weight component along the direction of motion and the second term is the friction force.

M cancels out. Solve for a.

## Answer This Question

## Related Questions

- Physics - A 75 kg box slides down a 25 degree ramp with an acceleration of 3.60 ...
- Physics - A 75 kg box slides down a 25.0 degree ramp with an acceleration of 3....
- Physics - A box slides down a 30.0 degree ramp with an acceleration of 1.20 m/s^...
- physics - A box of mass 5.0 kg starting from rest slides down a 1.8 m long ramp ...
- physics - A 475 gram box is given a push and it then slides up and back down a ...
- physics - A 75 kg box slides down a 25o ramp with an acceleration of 3.6 m/s2. ...
- physics - A box slides down a 30.0 degree ramp with an acceleration of 1.25m/s...
- physics - A 31 kg box slides down a 33.0 ramp with an acceleration of 1.30 m/s2...
- Physics - A box, with a weight of mg = 25 N, is placed at the top of a ramp and ...
- physics - A box slides down a 28° ramp with an acceleration of 0.98 m/s2. ...

More Related Questions