Tuesday

September 16, 2014

September 16, 2014

Posted by **Jen** on Friday, February 23, 2007 at 1:19pm.

Altitude CD is drawn to hypotenuse AB.

Prove AB/BC = BC/BD and AB/AC = AC/AD

This is a theorem. How do I prove it? Thanks.

Dont you have similar triangles? You can show this by looking at the angles involved...remember the altitude forms a perpendicular angle on the hypotenuse.

- Geometry- how to write proof -
**Anonymous**, Wednesday, May 14, 2014 at 11:28amABC WITH A=35,AC=6cm and C=65 a second triangle wit G=80,GH=9cm and H=35

**Answer this Question**

**Related Questions**

Geometry - The altitude to the hypotenuse of a right triangle ABC divides the ...

Math(Geometry) - In the diagram below(no diagram but details will be provided), ...

Geometry - In the diagram below, the length of the legs AC and BC of right ...

geometry - Given: In triangle ABC, <A=135 degree Prove: <B is not equal to...

geometry - right triangle ABC with right angle C, AC=22 and BC=6, altitude CD ...

college geometry - Given: right triangle ABC with right angle at C, AC=22 and BC...

geometry - the vertices of triangle ABC are A(1,7)B(9,3)C(3,1) a.prove that the ...

geometry - In a triangle ABC,right angled at B, BD is drawn perpendicular to AC...

Math - In right triangle ABC, altitude CD is drawn to hypotenuse AB. If AD ...

geometry - In the diagram below, the length of the legs AC and BC of right ...