Posted by **Jen** on Friday, February 23, 2007 at 1:19pm.

ABC is a right triangle. Angle C is 90 degree.

Altitude CD is drawn to hypotenuse AB.

Prove AB/BC = BC/BD and AB/AC = AC/AD

This is a theorem. How do I prove it? Thanks.

Dont you have similar triangles? You can show this by looking at the angles involved...remember the altitude forms a perpendicular angle on the hypotenuse.

## Answer This Question

## Related Questions

- geometry - Complete the flow proof for a Hypotenuse-Angle Theorem. Given AC ...
- Geometry - The altitude to the hypotenuse of a right triangle ABC divides the ...
- Math(Geometry) - In the diagram below(no diagram but details will be provided), ...
- PLEASE HELP!!!!! (Right Triangle Question) - Point N is on hypotenuse BC of ...
- geometry - Given: In triangle ABC, <A=135 degree Prove: <B is not equal to...
- Geometry - In the diagram below, the length of the legs AC and BC of right ...
- geometry - right triangle ABC with right angle C, AC=22 and BC=6, altitude CD ...
- honors/Geometry - how do you write out proofs? To be more specific with my ...
- college geometry - Given: right triangle ABC with right angle at C, AC=22 and BC...
- geometry - the vertices of triangle ABC are A(1,7)B(9,3)C(3,1) a.prove that the ...

More Related Questions