Friday

December 19, 2014

December 19, 2014

Posted by **em** on Friday, February 23, 2007 at 7:02am.

1) Simplify (sqroot)500

2) Simplify (sqroot)50 x (sqroot)60

Also..

Simplify the following fractions so that there is no root in the denominator:

1/(sqroot)5

12/(sqroot)3

Thankyou so much!

1) sqrt500 =sqrt(25 x4 x 5)

=(sqrt 25)x(sqrt4)x (Sqrt5)

=5 x 2 x (sqrt5)

=10sqrt5

therefore a=10 and b=5

2) sqrt50 xsqrt60 =Sqrt300

=sqrt25 x sqrt4 x sqrt3

=5 x 2 x sqrt3

=10sqrt3

therefore a=10 and b=3

**Answer this Question**

**Related Questions**

maths - Hi, could someone please tell me how I would go about working these out...

Math - Two positive integers are in ratio 1:3. If their sum is added to their ...

Maths - I got the last question so please dont worry.. These are the ones I get ...

Maths - The sum of the squares of three consecutive positive integers is 365 ...

MATHS - Critical help please. Level 3 maths algebraic methods is really hard. Q...

please i need help accounting - i have a promblem it gives me the information ...

maths - pplz tell me about maths working modals froom where can i down load then...

Maths- very very simple - can someone tell me what the title of this proof is? a...

Maths - The first year after 1999 which is the product of three consecutive ...

algebra - Can someone please help me with this? Solve x^3-3x^2-10x=0 by ...